question_answer

    If in the circuit, power dissipation is 150 W, then R is:

A)  \[2\,\Omega \]                               

B)  \[6\,\Omega \]

C)  \[5\,\Omega \]                               

D)  \[4\,\Omega \]

Correct Answer: B

Solution :

                \[P=\frac{{{V}^{2}}}{{{R}_{net}}}\]                 \[150=\frac{{{(15)}^{2}}}{\frac{R.2}{2+R}}\]                 \[R=6\,ohm\]