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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        Wavelength of light used in an optical instrument are\[{{\lambda }_{1}}=4000\,\overset{o}{\mathop{\text{A}}}\,\]and\[{{\lambda }_{2}}=5000\,\overset{o}{\mathop{\text{A}}}\,,\]then ratio of their respective resolving powers (corresponding to\[{{\lambda }_{1}}\]and\[{{\lambda }_{2}}\]) is:

    A)  \[16:25\]                            

    B)  \[9:1\]

    C)  \[4:5\]                                 

    D)  \[5:4\]

    Correct Answer: D

    Solution :

                    Resolving power of an optical instrument is inversely proportional to\[\lambda \]i.e.,\[R.P.\propto \frac{1}{\lambda }\] \[\therefore \] \[\frac{Resolving\text{ }power\text{ }at{{\lambda }_{1}}}{Resolving\text{ }power\text{ }at{{\lambda }_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\]                 \[=\frac{5000}{4000}=5:4\]


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