A) \[-6.8eV\]
B) \[-3.4eV\]
C) \[-1.51eV\]
D) \[-4.53eV\]
Correct Answer: C
Solution :
\[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\] For second excited state\[n=3,\] \[{{E}_{3}}=-\frac{13.6}{9}=-1.51\,eV\]You need to login to perform this action.
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