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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2006

  • question_answer
        The\[\Delta H_{f}^{o}\]for\[C{{O}_{2}}(g),CO(g)\]and\[{{H}_{2}}O(g)\] are \[-393.5,-110.5\] and \[-241.8~kJ/mol\] respectively. The standard enthalpy change (in kJ) for the reaction\[C{{O}_{2}}(g)+{{H}_{2}}(g)\xrightarrow[{}]{{}}CO(g)+{{H}_{2}}O(g)\]is

    A)  524.1                                   

    B)  41.2

    C)  \[-262.5\]                          

    D)  \[-41.2\]

    Correct Answer: B

    Solution :

                    Key Idea: \[\Delta H=\Sigma (\Delta H{{{}^\circ }_{products}})-\Sigma (\Delta H{{{}^\circ }_{reac\tan ts}})\] Given, \[\Delta H_{f}^{o}C{{O}_{2}}(g)=-393.5\text{ }kJ/mol\] \[\Delta H_{f}^{o}=CO(g)=-110.5\text{ }kJ/mol\] \[\Delta H_{f}^{o}{{H}_{2}}O(g)=-241.8\text{ }kJ/mol\] \[C{{O}_{2}}(g)+{{H}_{2}}(g)=-241.8\,kJ/mol\] \[C{{O}_{2}}(g)+{{H}_{2}}(g)\xrightarrow[{}]{{}}CO(g)+{{H}_{2}}O(g)\] \[\Delta H{}^\circ =[(\Delta H_{f}^{o}CO)+(\Delta H_{f}^{o}{{H}_{2}}O)]\] \[-[(\Delta H_{f}^{o}C{{O}_{2}})+(\Delta H_{f}^{o}{{H}_{2}})]\] \[=[(-110.5)+(-241.8)]\]                                                 \[-[(-393.5)+(0)]\] \[=-110.5-241.8+393.5\] \[=-352.3+393.5\] \[=+41.2\,kJ\]


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