A) zero
B) 1/3
C) 1/4
D) none of these
Correct Answer: D
Solution :
Key Idea: Any number is odd, if its units place is not 0, 2, 4, 6, 8. Given numbers are 1, 2, 3, 4 . Possible digits of unit digit of odd number is (either 1 or 3) = 2 Possibilities for tens digit = 3 Possibilities for hundred place digit = 2 Possibilities for thousand place digit = 1 \[\therefore \]Number of favorable outcomes \[=2\times 2\times 2\times 1=12\] Number of numbers formed by 1, 2, 3, 4 (without repetitions) = 41 \[\therefore \]Required probability\[=\frac{12}{4\times 3\times 2}=\frac{1}{2}\]
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