A) \[{{\sin }^{-1}}(\mu )\]
B) \[{{\tan }^{-1}}(\mu )\]
C) \[{{\cot }^{-1}}(\mu )\]
D) \[{{\tan }^{-1}}\left( \frac{1}{\mu } \right)\]
Correct Answer: B
Solution :
According to Brewsfers, if light reflected from the medium is plane polarised. Then angle of incidence is called polarisation angle or the Brewsters angle. This polarisation angle (i) depends on the refractive index of the medium. The tangent of the polarisation angle is equal to the refractive index of that reflection surface, ie, \[\mu =\tan i\] or \[i={{\tan }^{-1}}(\mu )\]
You need to login to perform this action.
You will be redirected in
3 sec
