A) \[\frac{q}{{{\varepsilon }_{0}}}\]
B) \[\frac{q}{6{{L}^{2}}{{\varepsilon }_{0}}}\]
C) \[\frac{6q{{L}^{2}}}{{{\varepsilon }_{0}}}\]
D) zero
Correct Answer: A
Solution :
From Gauss theorem, the electric flux\[(\phi )\]through any closed surface is equal to\[\frac{1}{{{\varepsilon }_{0}}}\]times the net charge q enclosed by the surface. Thus, \[\phi =\int{\overrightarrow{E}}.dA=\frac{q}{{{\varepsilon }_{0}}}\]You need to login to perform this action.
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