A) One molal\[NaCl\]aqueous solution
B) One molal\[CaCla\]aqueous solution
C) One molal\[KCl\]aqueous solution
D) One molal urea aqueous solution
Correct Answer: B
Solution :
Key Idea: Depression in freezing point is colligative property. The solute which produces highest number of ions will have minimum freezing point. (a) One molal\[NaCl\]aqueous solution \[\xrightarrow[{}]{{}}N{{a}^{+}}+C{{l}^{-}}\] \[\therefore \]2 ions/ molecule (b) one molal\[KCl\]aqueous solution \[\xrightarrow[{}]{{}}{{K}^{+}}+C{{l}^{-}}\] \[\therefore \]2 ions/ molecule (c) One molal urea aqueous solution\[\xrightarrow[{}]{{}}\] no dissociation (d) One molal\[CaC{{l}_{2}}\]solution \[CaC{{l}_{2}}\xrightarrow[{}]{{}}C{{a}^{2+}}+2C{{l}^{-}}\] \[\therefore \]3ions/molecule \[\because \] \[CaC{{l}_{2}}\] solution has highest number of ions \[\therefore \]It has lowest freezing point. Key Idea: Proton donors are acids Electrons withdrawing groups increase aridity. More the umber of electrons withdrawing groups more ill be acidity. Closer the electrons withdrawing group to proton more will be acidity. \[\therefore \]\[C{{l}_{2}}CHCOOH,\]has highest acidity among \[C{{H}_{3}}COOH,ClC{{H}_{2}}COOH,C{{l}_{2}}CHCOOH,\] \[C{{l}_{2}}CHC{{H}_{2}}COOH\]
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