A) \[\frac{n{{h}^{2}}}{4\pi }\]
B) \[\frac{{{n}^{2}}{{h}^{2}}}{4\pi }\]
C) \[\frac{\sqrt{n{{h}^{2}}}}{4\pi }\]
D) \[\frac{nh}{2\pi }\]
Correct Answer: D
Solution :
Angular momentum of electrons\[=mvr=\frac{nh}{2\pi }\]
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