A) \[BaC{{l}_{2}}\]
B) \[KCN\]
C) \[NaN{{O}_{3}}\]
D) \[N{{H}_{4}}SCN\]
Correct Answer: D
Solution :
Key Idea: The chemical compounds to be distinguished should give different colouration with reagent \[F{{e}^{2+}}+N{{H}_{4}}SCN\xrightarrow[{}]{{}}NoChangeincolour\] \[F{{e}^{3+}}+N{{H}_{4}}SCN\xrightarrow[{}]{{}}Red\text{ }colouration\] \[\therefore \]\[N{{H}_{4}}SCN\]is used to distinguish between \[F{{e}^{2+}}\]and\[F{{e}^{3+}}\]
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