A) Phenol
B) Benzaldehyde
C) Butanal
D) Benzoic acid
Correct Answer: B
Solution :
\[A+NaOH\to alcohol+acid\] Thus it is Cannizaro reaction. A is thus aldehyde without H at\[\alpha -\]carbon. (as\[{{C}_{6}}{{H}_{5}}CHO,\text{ }HCHO\]) \[2{{C}_{6}}{{H}_{5}}CHO+NaOH\xrightarrow[{}]{{}}{{C}_{6}}{{H}_{5}}C{{H}_{2}}OH\] \[+{{C}_{6}}{{H}_{5}}COONa\]
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