A) 5
B) \[-21\]
C) \[{{3}^{8}}\]
D) \[^{8}{{C}_{3}}\]
Correct Answer: B
Solution :
The required number of ways\[{{=}^{8-1}}{{C}_{3-1}}\] \[{{=}^{7}}{{C}_{2}}=\frac{7!}{2!5!}\] \[=\frac{7.6}{2.1}=21\]
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