JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2007

  • question_answer
        The value of\[\int_{0}^{\pi /2}{\frac{{{(\sin x+\cos x)}^{2}}}{\sqrt{1+\sin 2x}}}dx\]is

    A)  0                                            

    B)  1

    C)  2                                            

    D)  3

    Correct Answer: C

    Solution :

                    Let \[I=\int_{0}^{\pi /2}{\frac{{{(\sin x+\cos x)}^{2}}}{\sqrt{{{\sin }^{2}}x+{{\cos }^{2}}x+2\sin x\cos x}}}dx\] \[I=\int_{0}^{\pi /2}{\frac{{{(\sin x+\cos x)}^{2}}}{\sqrt{{{(\sin x+\cos x)}^{2}}}}}dx\] \[I=\int_{0}^{\pi /2}{(\sin x+\cos x)}dx\] \[I=[-\cos x+\sin x]_{0}^{\pi /2}\] \[I=-\cos \frac{\pi }{2}+\sin \frac{\pi }{2}+\cos 0-\sin 0\] \[I=-0+1+1-0=2\]


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