A) \[19.8\times {{10}^{-7}}kg\]
B) \[9.9\times {{10}^{-7}}kg\]
C) \[6.6\times {{10}^{-7}}kg\]
D) \[1.1\times {{10}^{-7}}kg\]
Correct Answer: A
Solution :
Mass of substance liberated at cathode \[m=zit\] where,\[z=\]electro-chemical equivalent \[=3.3\times {{10}^{-7}}kg/C\] \[i=\]current flowing\[=3A,\] \[t=2s\] \[\therefore \] \[m=3.3\times {{10}^{-7}}\times 3\times 2=19.8\times {{10}^{-7}}kg\]
You need to login to perform this action.
You will be redirected in
3 sec
