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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2007

  • question_answer
        A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earths magnetic field is\[0.2\times {{10}^{-4}}T,\]then the emf developed between the two ends of the conductor is

    A)  \[5\mu V\]                                        

    B)  \[5\mu V\]

    C)  \[5mV\]                             

    D)  \[50\,mV\]

    Correct Answer: B

    Solution :

                    The emf induced between ends of conductor \[e=\frac{1}{2}B\omega {{L}^{2}}\]                 \[=\frac{1}{2}\times 0.2\times {{10}^{-4}}\times 5\times {{(1)}^{2}}\]                 \[=0.5\times {{10}^{-4}}V\]                 \[=5\times {{10}^{-5}}V=50\,\mu V\]


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