A) \[L{{i}^{+}}\]
B) \[{{B}^{3+}}\]
C) \[{{O}^{2-}}\]
D) \[{{F}^{-}}\]
Correct Answer: C
Solution :
All the ions belong to same period thus for them cations will be smaller than anions. Now, \[{{O}^{2-}}\]and\[{{F}^{-}}\]are isoelectronic and\[{{r}_{n}}\propto \frac{1}{Z}\] Thus ionic radius of\[{{O}^{2-}}(Z=8)>{{F}^{-}}(Z=9)\]
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