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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2007

  • question_answer
        An ideal gas expands in volume from \[1\times {{10}^{-3}}{{m}^{3}}\]to\[1\times {{10}^{-2}}{{m}^{3}}\]at 300K against a constant pressure of\[1\times {{10}^{5}}N{{m}^{-2}}\]. The work done is              

    A)  \[-900J\]                            

    B)  \[-900\text{ }kJ\]

    C)  \[270kJ\]                            

    D)  \[900kJ\]

    Correct Answer: A

    Solution :

                    Work done due to change in volume against constant pressure is \[W=-P({{V}_{2}}-{{V}_{1}})\]                 \[=-1\times {{10}^{5}}N{{m}^{-2}}(1\times {{10}^{-2}}-1\times {{10}^{-3}}){{m}^{3}}\]                 \[=-900Nm=-900J\]         \[(1\,Nm=1J)\]


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