2. Solved Papers
  3. JAMIA MILLIA ISLAMIA

JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2007

  • question_answer
        The enthalpies of combustion of carbon and carbon monoxide are\[-393.5\]and\[-283k\text{ }J\] \[mo{{l}^{-1}}\]respectively. The enthalpy of formation of carbon monoxide per mole is

    A)  110.5kJ                               

    B)  676.5 kJ

    C)  \[-676.5\text{ }kJ\]        

    D) \[-110.5kJ\]

    Correct Answer: D

    Solution :

                    I: \[C(s)+{{O}_{2}}(g)\xrightarrow[{}]{{}}C{{O}_{2}}(g)\]\[\Delta H=-393.5\,kJ\] II: \[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}C{{O}_{2}}(g),\]                                                 \[\Delta H=-283.0\,kJ\] \[I-II\] gives III:\[C(s)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}CO(g),\] \[\Delta H=-110.5\,kJ\] This equation III also represents formation of one mol of CO and thus enthalpy change is the heat of formation of CO (g).


You need to login to perform this action.
You will be redirected in 3 sec spinner