2. Solved Papers
  3. JAMIA MILLIA ISLAMIA

JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2007

  • question_answer
        Consider the following nuclear reactions: \[_{92}^{238}M\to _{y}^{x}N+2_{2}^{4}He;_{y}^{x}N\to _{B}^{A}L+2{{\beta }^{+}}\] The number of neutrons in the element L is

    A)  142                                       

    B)  144

    C)  140                                       

    D)  146

    Correct Answer: B

    Solution :

                    \[_{92}^{238}M\xrightarrow[{}]{{}}_{Y}^{X}N+2_{2}^{4}He\] \[X=230\] \[Y=88\] \[_{88}^{230}N\xrightarrow[{}]{{}}_{B}^{A}L+2_{1}^{0}e({{\beta }^{+}})\] \[\therefore \]                  \[A=230\] \[=n+p\] \[\therefore \]                  \[B=86=p\] \[\therefore \]                  \[n=144\]           


You need to login to perform this action.
You will be redirected in 3 sec spinner