A) \[F{{e}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}\]
B) \[N{{a}_{3}}[Fe{{(CN)}_{6}}]\]
C) \[Fe{{(CN)}_{3}}\]
D) \[N{{a}_{4}}[Fe{{(CN)}_{5}}NOS]\]
Correct Answer: A
Solution :
If nitrogen is present in organic compound then sodium extract contains\[N{{a}_{4}}[Fe{{(CN)}_{6}}]\]. \[Na+C+N\xrightarrow[{}]{fuse}NaCN\] \[FeS{{O}_{4}}+6NaCN\xrightarrow[{}]{{}}\underset{(A)}{\mathop{N{{a}_{4}}[fe{{(CN)}_{6}}]}}\,+N{{a}_{2}}S{{O}_{4}}\] A changes to Prussian blue \[F{{e}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}\] on reaction with\[FeC{{l}_{3}}\]. \[4FeC{{l}_{3}}+3N{{a}_{4}}[Fe{{(CN)}_{6}}]\xrightarrow[{}]{{}}\] \[F{{e}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}+12NaCl\]
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