A) Acetone
B) Acetic acid
C) Acetonitrile
D) Acetamide
Correct Answer: C
Solution :
(a) \[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\underset{s{{p}^{2}}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}}\,\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\] (b) \[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\underset{s{{p}^{2}}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}}\,\underset{{}}{\mathop{OH}}\,\] (c) \[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{sp}{\mathop{C}}\,\equiv N\] (d)\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\underset{s{{p}^{2}}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}}\,\underset{{}}{\mathop{N{{H}_{2}}}}\,\] Acetonitrile does not contain\[s{{p}^{2}}\]hybridized carbon.
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