A) \[\frac{100}{101}\]
B) \[\frac{99}{100}\]
C) \[1\]
D) \[2\]
Correct Answer: C
Solution :
The frequency of sonometer wire is \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] Taking logarithm and differentiate, we get \[\frac{\Delta n}{n}=\frac{\Delta l}{l}+\frac{1}{2}\frac{\Delta T}{T}+\frac{1}{2}\frac{\Delta m}{m}\] \[\therefore \] \[\frac{\Delta n}{n}=\frac{\Delta l}{l}+0+0\] \[=1%\] Hence, frequency will increase by 1%.
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