A) anhydrous \[AlC{{l}_{3}}\]
B) \[FeC{{l}_{3}}\]
C) anyhydrous \[ZnC{{l}_{2}}\]
D) \[Cu\]
Correct Answer: C
Solution :
\[-OH\]group is converted into\[-Cl\]group by\[SOC{{l}_{2}}\]or anhy.\[ZnC{{l}_{2}}\]/conc.\[HCl\]or\[HCl\]etc.
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