A) \[N{{H}_{3}}\]
B) \[N{{H}_{2}}OH\]
C) \[NH_{4}^{+}\]
D) \[{{N}_{2}}{{H}_{4}}\]
Correct Answer: A
Solution :
\[NH_{2}^{-}(base)+{{H}^{+}}\to N{{H}_{3}}\](conjugate acid)
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