A) 3
B) 4
C) 8
D) 16
Correct Answer: B
Solution :
\[\frac{{{A}_{0}}}{{{2}^{n}}}=\frac{{{A}_{0}}}{16}\] \[\therefore \] \[\frac{1}{{{2}^{n}}}=\frac{1}{{{2}^{4}}}\] So n ie, of half lives =4
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