A) \[2.0\times {{10}^{-5}}/{}^\circ C\]
B) \[4.0\times {{10}^{-5}}/{}^\circ C\]
C) \[6.0\times {{10}^{-5}}/{}^\circ C\]
D) \[8.0\times {{10}^{-5}}/{}^\circ C\]
Correct Answer: A
Solution :
Since\[\gamma =\frac{\Delta V}{V\Delta T}\] \[\Rightarrow \] \[\gamma =\frac{0.12}{100}\times \frac{1}{20}\] \[\Rightarrow \] \[\gamma =6\times {{10}^{-5}}/{}^\circ C\] \[\therefore \] \[\alpha =\frac{\gamma }{3}\] \[\Rightarrow \] \[\alpha =\frac{6\times {{10}^{-5}}}{3}=2.0\times {{10}^{-5}}/{}^\circ C\]
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