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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2009

  • question_answer
        lf \[x+y+z=xyz,\]then \[ta{{n}^{-1}}x+ta{{n}^{-1}}y+ta{{n}^{-1}}z\] is equal to

    A)  \[\pi \]                                

    B)  \[\frac{\pi }{2}\]

    C)  1                                            

    D)  None of these

    Correct Answer: A

    Solution :

                    \[{{\tan }^{-1}}x+{{\tan }^{-1}}y+{{\tan }^{-1}}z\]\[={{\tan }^{-1}}\left[ \frac{x+y+z-xyz}{1-(xy+yz+zx)} \right]\]\[={{\tan }^{-1}}0=\pi \]


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