JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2009

  • question_answer
        If G is the GM of the product of r set of observation    with    geometric    means\[{{G}_{1}},{{G}_{2}},....{{G}_{r}}\]respectively, then G is equal to

    A)  \[\log {{G}_{1}}+\log {{G}_{2}}+....+\log {{G}_{n}}\]

    B)  \[{{G}_{1}}{{G}_{2}}....{{G}_{n}}\]

    C)  \[\log {{G}_{1}},\log {{G}_{2}},....,\log {{G}_{n}}\]

    D)  None of the above

    Correct Answer: B

    Solution :

                    Taking\[x\]as the product of variates\[{{x}_{1}},{{x}_{2}},.....,{{x}_{r}}\]corresponding to r set of observation ie, \[x={{x}_{1}}{{x}_{2}}.....{{x}_{r}},\]we have \[\log x=\log \text{ }{{x}_{1}}+\log \text{ }{{x}_{2}}+...+\log \text{ }{{x}_{r}}\] \[\Rightarrow \] \[\Sigma \log x=\Sigma \log \text{ }{{x}_{1}}+\Sigma \log \text{ }{{x}_{2}}+...+\Sigma \log \text{ }{{x}_{r}}\] \[\Rightarrow \] \[\frac{1}{n}\Sigma \log x=\frac{1}{n}\Sigma \log \text{ }{{x}_{1}}+\frac{1}{n}\Sigma \log \text{ }{{x}_{2}}\]                                                 \[+...+\frac{1}{n}\Sigma \log \text{ }{{x}_{r}}\] \[\Rightarrow \] \[\log G=\log {{G}_{1}}+\log {{G}_{2}}+....+\log {{G}_{r}}\] \[\Rightarrow \]               \[G={{G}_{1}}{{G}_{2}}......{{G}_{r}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner