A) \[T\]
B) \[\sqrt{\frac{9}{10}}T\]
C) \[\sqrt{\frac{10}{9}}T\]
D) \[\frac{T}{10}\]
Correct Answer: C
Solution :
Net weight of pendulum equals \[W=W-{{U}_{th}}\] \[\Rightarrow \] \[W={{V}_{eg}}-\frac{Veg}{10}\] \[\Rightarrow \] \[W=\frac{9}{10}W\] \[\Rightarrow \] \[mg=\frac{9}{10}mg\] \[(\because W=mg)\] \[\Rightarrow \] \[g=\frac{g}{10}mg\] \[\therefore \] \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[T=\sqrt{\frac{10}{9}}T\]You need to login to perform this action.
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