A) \[h\]
B) \[\frac{h}{3\pi }\]
C) \[\frac{h}{2\pi }\]
D) \[\frac{h}{4\pi }\]
Correct Answer: C
Solution :
Let electron jump from \[{{n}_{1}}\to {{n}_{2}}\] So, \[\Delta L=({{n}_{2}}-{{n}_{1}})\frac{h}{2\pi }\] (According to Bohrs quantitation rule) Since,\[{{n}_{1}}\]and\[{{n}_{2}}\]are integers\[({{n}_{1}},{{n}_{2}}>1),\]so \[{{n}_{2}}-{{n}_{1}}\] is also an integral value and hence,\[\Delta L\]must be an integral multiple of\[\frac{h}{2\pi }\].
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