A) \[9\times {{10}^{10}}J\]
B) \[9\times {{10}^{19}}J\]
C) \[9\times {{10}^{18}}J\]
D) \[9\times {{10}^{17}}J\]
Correct Answer: A
Solution :
\[E=m{{c}^{2}}\] \[\therefore \] \[E=({{10}^{-6}})\times (9\times {{10}^{16}})\] \[E=9\times {{10}^{10}}J\]
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