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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2009

  • question_answer
        A heat engine absorbs heat at\[327{}^\circ C\]and exhausts heat at\[127{}^\circ C\]. The efficiency of engine is\[\eta \]and the maximum amount of work performed by the engine per kilocalorie of heat input is W. Then

    A) \[\eta =0.38\]                                   

    B)  \[\eta =0.88\]

    C)  \[W=1596J\]    

    D)  \[W=1400J\]

    Correct Answer: D

    Solution :

                    \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{127+273}{327+273}=\frac{3-2}{3}\] \[\eta =\frac{1}{3}\] Further \[\eta =\frac{W}{Q}\] \[\Rightarrow \]               \[W=Q\eta =\frac{1000}{3}cal\] \[\Rightarrow \]               \[W=\frac{1000\times 4.2}{3}J\] \[\Rightarrow \]               \[W=1400\,J\]


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