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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2009

  • question_answer
        A 2 kg block is dropped from a height of 0.4m on a spring of force constant\[k=1960\text{ }N{{m}^{-1}}\]. The maximum compression of the spring is

    A)  0.1 m                                   

    B)  0.2 M

    C)  0.3 M                                   

    D)  0.4 M

    Correct Answer: A

    Solution :

                    By law of conservation of energy, we have loss in gravitational potential energy = gain in elastic potential energy \[\Rightarrow \]               \[mg(h+x)=\frac{1}{2}k{{x}^{2}}\]                            \[2\times 10(0.4+x)=\frac{1}{2}1960\times {{x}^{2}}\] \[\Rightarrow \]               \[8+20x=980{{x}^{2}}\] \[\Rightarrow \]               \[980{{x}^{2}}-20x-8=0\] Solving, we get \[x=0.1\text{ }m\]


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