JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2009

  • question_answer
        Which of the following radical is precipitated as sulphide when treated with hydrogen sulphide in ammonia Cal solution?

    A)  \[B{{a}^{2+}}\]                                

    B)  \[N{{i}^{2+}}\]

    C)  \[M{{g}^{2+}}\]                              

    D)  \[C{{a}^{2+}}\]

    Correct Answer: D

    Solution :

                    \[N{{i}^{2+}}\]is present in fourth group in the identification of basic radical other radicals are \[C{{O}^{2+}},Z{{n}^{2+}}\]and\[M{{n}^{2+}}\]The group reagent is hydrogen sulphide in ammoniacal solution. Radicals are precipitate as sulphide which are insoluble in\[N{{H}_{4}}OH\] \[CoS,\text{ }NiS\]          forms                    Black ppt. \[MnS\]               forms                    Buff ppt. \[ZnS\]                 forms                    white ppt.


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