A)
B)
C)
D)
Correct Answer: C
Solution :
Volume of 1 mole of an ideal gas at 273 K and 1 atm pressure = 22.4 L \[\therefore \]volume at 373 K and 1 atm pressure will be given by \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\](at constant p) \[={{V}_{2}}=30.6L\] \[=\frac{22.4}{273}=\frac{V}{373}\] \[{{V}_{2}}=30.6L\]
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