A) electrolysis of molten \[CaC{{l}_{2}}\]
B) electrolysis of aq solution of \[CaC{{l}_{2}}\]
C) reduction of\[CaC{{l}_{2}}\]with carbon
D) roasting of lime stone
Correct Answer: A
Solution :
In molten state \[CaC{{l}_{2}}\xrightarrow[{}]{{}}C{{a}^{2+}}+2C{{l}^{-}}\]At cathode \[C{{a}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Ca\]\[C{{a}^{2+}}\]ion cannot be reduced in aqueous solution as\[E{}^\circ C{{a}^{2+}}/Ca<E{}^\circ {{H}_{2}}O\](water would be reduced in preference) \[C{{a}^{2+}}\]cannot be reduced by carbon. On heating\[Ca\]carbonate produce\[CaO\]and\[C{{O}_{2}}\].
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