A) Distilled water
B) \[1M\,N{{H}_{3}}\]
C) \[1M\,NaOH\]
D) Water saturated with chlorine
Correct Answer: C
Solution :
Pure water has \[pH=7\] \[N{{H}_{3}}\]solution is weakly, basic. So,\[pH>7\]but not too large for\[1\text{ }M\text{ }NaOH,\text{ }\!\![\!\!\text{ }O{{H}^{-}}]=1,\] \[[{{H}^{+}}]=\frac{{{10}^{-14}}}{[O{{H}^{-}}]}={{10}^{-14}}\] Hence, \[pH=-log\text{ }{{10}^{-14}}=14.\] \[C{{l}_{2}}+HO\xrightarrow[{}]{{}}HCl+HClO\] Hence, the solution is acid or\[pH<7\].
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