A) \[1256\times {{10}^{-26}}A{{m}^{2}}\]
B) \[6.53\times {{10}^{-26}}A{{m}^{2}}\]
C) zero
D) \[256\times {{10}^{-26}}A{{m}^{2}}\]
Correct Answer: A
Solution :
\[M=I\text{ }A=(ev)\text{ }\pi {{r}^{2}}\] \[=1.6\times {{10}^{-19}}\times {{10}^{16}}\times \frac{22}{7}\times {{(0.5\times {{10}^{-10}})}^{2}}\] \[=1256\times {{10}^{-26}}\,A{{m}^{2}}\]
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