A) no action occurs
B) \[{{H}_{2}}\]is formed
C) \[NaO{{C}_{2}}{{H}_{5}}\]and\[{{O}_{2}}\]are formed
D) \[NaO{{C}_{2}}{{H}_{5}}\]and\[{{H}_{2}}\]are formed
Correct Answer: D
Solution :
When sodium is added to ethanol, alkoxide and\[{{H}_{2}}\]gas is formed. \[\underset{ethanol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+Na\xrightarrow[{}]{{}}\underset{sodium\text{ }ethoxide}{\mathop{{{C}_{2}}{{H}_{5}}\overset{-}{\mathop{O}}\,\overset{+}{\mathop{N}}\,a}}\,+\frac{1}{2}{{H}_{2}}\]
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