A) \[7.5\times {{10}^{-5}}A\]
B) \[7.5\times {{10}^{-4}}A\]
C) \[7.5\times {{10}^{-3}}A\]
D) \[7.5\times {{10}^{-2}}A\]
Correct Answer: D
Solution :
Here, the resistances\[10\,\Omega ,60\,\Omega \] and\[100\,\Omega ,\]are in series and they together are in parallel to \[200\,\Omega ,\]resistance. When a potential difference of 15 V is applied across\[200\,\Omega ,\]then current through it is \[I=\frac{15}{200}=7.5\times {{10}^{-2}}A\] Magnetic field at the centre of circular loop.You need to login to perform this action.
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