A) \[4s\]
B) \[2s\]
C) \[4\sqrt{2}s\]
D) None of these
Correct Answer: A
Solution :
Pole strength of each pole is halved but length is same, so its magnetic moment becomes half. As mass of each part is halved, moment of inertia\[I\]is halved. As \[T=2\pi \sqrt{\frac{I}{MB}}\] \[\therefore \] \[T=\sqrt{\frac{I/2}{(M/2)B}}=T\] Hence, T remains the same is 4 s.You need to login to perform this action.
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