A) acetic acid
B) ethyl alcohol
C) ethylene glycol
D) oxalic acid
Correct Answer: D
Solution :
\[\underset{CH}{\overset{CH}{\mathop{|||}}}\,+4[O]\xrightarrow[{}]{alkaline\,KMn{{O}_{4}}}\underset{oxalic\text{ }acid}{\mathop{\underset{COOH}{\overset{COOH}{\mathop{|}}}\,}}\,\]
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