A) 2.1
B) 3.1
C) 3.2
D) 4.1
Correct Answer: D
Solution :
The balanced chemical equation is \[\underset{\begin{smallmatrix} 1\,mol \\ \,\,\,\,? \end{smallmatrix}}{\mathop{{{N}_{2}}}}\,+3{{H}_{2}}\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} 2\,mol \\ 8.2\,mol \end{smallmatrix}}{\mathop{2N{{H}_{3}}}}\,\] 2 moles of\[N{{H}_{3}}\]are produced from\[{{N}_{2}}=1\]mol \[\therefore \]8.2 moles of\[N{{H}_{3}}\]will be produced from\[{{N}_{2}}\] \[=\frac{1}{2}\times 8.2\] \[=4.1\text{ }mol\]
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