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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2010

  • question_answer
        The temperature of a gas in a closed container is\[27{}^\circ C\]. If the temperature is raised to\[327{}^\circ C,\]the pressure exerted is

    A)  reduced to half

    B)  doubled

    C)  reduced to one third

    D)  cannot be predicted

    Correct Answer: B

    Solution :

                    \[\frac{{{p}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}}{{{T}_{2}}}\] Given,   \[{{T}_{1}}=27+273=300\text{ }K\] \[{{T}_{2}}=327+273=600\text{ }K\] So,          \[\frac{{{p}_{1}}}{300}=\frac{{{p}_{2}}}{600}\] \[\therefore \]  \[{{P}_{2}}=\frac{600}{300}{{p}_{1}}=2{{p}_{1}}\]ie, pressure becomes doubled.


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