2. Solved Papers
  3. JAMIA MILLIA ISLAMIA

JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        Two cells connected in series have electromotive force of 1.5 V each. Their internal resistance are\[0.5\,\Omega \]. and\[0.25\,\Omega \] respectively. This combination is connected to a resistance of\[2.25\,\Omega \]. Potential difference across the terminals of each cell

    A)  IV, 0.25V            

    B)  IV, 1.25V

    C)  1.5V, 2.25V       

    D)  1.5V, 2.56V

    Correct Answer: B

    Solution :

                    The arrangement is shown in the figure. The effective emf in the circuit is \[E=1.5+1.5=3.0V\]and the total resistance is \[R=0.5+0.25+2.25=3.0\text{ }\Omega .\] Hence, the current in the circuit is \[I=\frac{E}{R}=\frac{3.0}{3.0}=1.0A\] Potential difference across the terminals of the first cell is \[{{V}_{1}}=E-I{{r}_{1}}=1.5-(1.0)\times (0.5)=1.0\,V\] Potential difference across the terminals of the second cell is \[{{V}_{2}}=E-I{{r}_{2}}=1.5-(1.0)\times (0.25)=1.25\,V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner