2. Solved Papers
  3. JAMIA MILLIA ISLAMIA

JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        The vapour pressure of water at\[23{}^\circ C\]is i9.8 mm of Hg.0.1 mol of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm Hg) of the resultant solution?

    A)  19.0                                      

    B)  19.602

    C)  19.402                                 

    D)  19.202

    Correct Answer: B

    Solution :

                    Moles of glucose; \[n{{C}_{6}}{{H}_{12}}{{O}_{6}}=0.1\] Moles of water; \[{{n}_{{{H}_{2}}O}}=\frac{178.2}{18}=9.9\] Mole fraction of water,                 \[{{x}_{{{H}_{2}}O}}=\frac{9.9}{9.9+0.1}=0.99\] \[{{P}_{solution}}={{P}_{solvent}}\times {{x}_{solvent}}\] \[=19.8\times 0.99\] \[=19.602mm\text{ }Hg\]


You need to login to perform this action.
You will be redirected in 3 sec spinner