A) \[{{H}_{2}}O\]
B) \[{{H}_{2}}S\]
C) \[{{H}_{2}}Se\]
D) \[{{H}_{2}}Te\]
Correct Answer: B
Solution :
In general, boiling points of hydrides increases on moving down the group but\[{{H}_{2}}O\]has the highest boiling point due to H-bonding. Thus,\[{{H}_{2}}S\]has the lowest/boiling point.
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