A) \[1\times {{10}^{2}}c{{m}^{3}}\]
B) \[2\times {{10}^{2}}c{{m}^{3}}\]
C) \[1.763\times {{10}^{2}}c{{m}^{3}}\]
D) None of these
Correct Answer: B
Solution :
Using the relation for volume \[V=length\times breadth\times thickness\] \[=12\times 6\times 2.45=176.4\] \[=1.764\times {{10}^{2}}c{{m}^{3}}\] The minimum number of significant figures is 1 in thickness, hence the volume will contain only one significant figure. Therefore, \[V=2\times {{10}^{2}}c{{m}^{3}}\]
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