JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2012

  • question_answer
    For one mole of an ideal gas, increasing the temperature from\[10{}^\circ C\]to\[20{}^\circ C\]

    A)  increases the average kinetic energy by two times

    B)  increases the rms velocity by\[\sqrt{2}\]times

    C)  increases the rms velocity by two times

    D)  increases both the average kinetic energy and rms velocity, but not significantly

    Correct Answer: D

    Solution :

                    Given, \[{{T}_{1}}=273+10=283\text{ }K\] \[{{T}_{2}}=273+20=293K\] Average \[KE=\frac{3}{2}KT\]                 \[\frac{(K{{E}_{1}})}{(K{{E}_{2}})}=\frac{283}{293}=0.96\] Root mean square (rms) velocity,                 \[{{v}_{rms}}=\sqrt{\frac{3RY}{M}}\]       \[\frac{{{v}_{{{(rms)}_{1}}}}}{{{v}_{{{(rms)}_{2}}}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}=\sqrt{\frac{283}{293}}=0.98\] Thus, both average kinetic energy and root mean square velocity increase but not significantly when temperature is increased from\[10{}^\circ C\]to\[20{}^\circ C\].


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