A) \[N{{H}_{3}}>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}\]
B) \[P{{H}_{3}}<As{{H}_{3}}<N{{H}_{3}}<Sb{{H}_{3}}\]
C) \[N{{H}_{3}}<P{{H}_{3}}<Sb{{H}_{3}}<As{{H}_{3}}\]
D) \[N{{H}_{3}}<P{{H}_{3}}<As{{H}_{3}}<Sb{{H}_{3}}\]
Correct Answer: B
Solution :
The boiling point of NH3 is higher due to the presence of hydrogen bonding. The order of boiling point of the hydrides of nitrogen family is asHydride: \[P{{H}_{3}}<As{{H}_{3}}<N{{H}_{3}}<Sb{{H}_{3}}\] B.P.: \[185~~~~~218~~~~~~~239.6~~~\,\,\,\,256\]
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